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339314035 = 5102166467
BaseRepresentation
bin10100001110011…
…000010101110011
3212122110221100111
4110032120111303
51143331022120
653400402151
711260056514
oct2416302563
9778427314
10339314035
11164596725
1295776357
13553b4348
14330c8a0b
151ebc775a
hex14398573

339314035 has 8 divisors (see below), whose sum is σ = 407581776. Its totient is φ = 271181280.

The previous prime is 339314023. The next prime is 339314039. The reversal of 339314035 is 530413933.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 339314035 - 213 = 339305843 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 339313988 and 339314006.

It is not an unprimeable number, because it can be changed into a prime (339314039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28129 + ... + 38338.

It is an arithmetic number, because the mean of its divisors is an integer number (50947722).

Almost surely, 2339314035 is an apocalyptic number.

339314035 is a deficient number, since it is larger than the sum of its proper divisors (68267741).

339314035 is a wasteful number, since it uses less digits than its factorization.

339314035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67493.

The product of its (nonzero) digits is 14580, while the sum is 31.

The square root of 339314035 is about 18420.4786854197. The cubic root of 339314035 is about 697.4835048749.

Adding to 339314035 its reverse (530413933), we get a palindrome (869727968).

The spelling of 339314035 in words is "three hundred thirty-nine million, three hundred fourteen thousand, thirty-five".

Divisors: 1 5 1021 5105 66467 332335 67862807 339314035