Base | Representation |
---|---|
bin | 110001011110100001000… |
… | …011101000011111101101 |
3 | 110001001001022202111020120 |
4 | 301132201003220133231 |
5 | 421201220412341323 |
6 | 11121540450235153 |
7 | 500433460325040 |
oct | 61364103503755 |
9 | 13031038674216 |
10 | 3400021215213 |
11 | 10a0a39379407 |
12 | 46ab44285ab9 |
13 | 1b880b68880c |
14 | ba7c1c1cc57 |
15 | 5d697e2d5e3 |
hex | 317a10e87ed |
3400021215213 has 8 divisors (see below), whose sum is σ = 5180984708928. Its totient is φ = 1942869265824.
The previous prime is 3400021215161. The next prime is 3400021215251. The reversal of 3400021215213 is 3125121200043.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3400021215213 - 210 = 3400021214189 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3400021215263) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80952886056 + ... + 80952886097.
It is an arithmetic number, because the mean of its divisors is an integer number (647623088616).
Almost surely, 23400021215213 is an apocalyptic number.
It is an amenable number.
3400021215213 is a deficient number, since it is larger than the sum of its proper divisors (1780963493715).
3400021215213 is a wasteful number, since it uses less digits than its factorization.
3400021215213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161905772163.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 3400021215213 its reverse (3125121200043), we get a palindrome (6525142415256).
The spelling of 3400021215213 in words is "three trillion, four hundred billion, twenty-one million, two hundred fifteen thousand, two hundred thirteen".
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