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3400032510401 is a prime number
BaseRepresentation
bin110001011110100001101…
…110101110000111000001
3110001001002010000100022212
4301132201232232013001
5421201231310313101
611121541532311505
7500433655330442
oct61364156560701
913031063010285
103400032510401
1110a0a4479367a
1246ab48012595
131b8810b11a67
14ba7c351d2c9
155d698e101bb
hex317a1bae1c1

3400032510401 has 2 divisors, whose sum is σ = 3400032510402. Its totient is φ = 3400032510400.

The previous prime is 3400032510377. The next prime is 3400032510451. The reversal of 3400032510401 is 1040152300043.

3400032510401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3375483888001 + 24548622400 = 1837249^2 + 156680^2 .

It is a cyclic number.

It is not a de Polignac number, because 3400032510401 - 26 = 3400032510337 is a prime.

It is not a weakly prime, because it can be changed into another prime (3400032510451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700016255200 + 1700016255201.

It is an arithmetic number, because the mean of its divisors is an integer number (1700016255201).

Almost surely, 23400032510401 is an apocalyptic number.

It is an amenable number.

3400032510401 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400032510401 is an equidigital number, since it uses as much as digits as its factorization.

3400032510401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 3400032510401 its reverse (1040152300043), we get a palindrome (4440184810444).

The spelling of 3400032510401 in words is "three trillion, four hundred billion, thirty-two million, five hundred ten thousand, four hundred one".