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340007035 = 568001407
BaseRepresentation
bin10100010001000…
…001100001111011
3212200210010222011
4110101001201323
51144020211120
653423310351
711266004104
oct2421014173
9780703864
10340007035
11164a1a355
1295a4b3b7
13555978c4
14332293ab
151ecb2c5a
hex1444187b

340007035 has 4 divisors (see below), whose sum is σ = 408008448. Its totient is φ = 272005624.

The previous prime is 340007027. The next prime is 340007047. The reversal of 340007035 is 530700043.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530700043 = 1648732189.

It is a cyclic number.

It is not a de Polignac number, because 340007035 - 23 = 340007027 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340006997 and 340007015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34000699 + ... + 34000708.

It is an arithmetic number, because the mean of its divisors is an integer number (102002112).

Almost surely, 2340007035 is an apocalyptic number.

340007035 is a deficient number, since it is larger than the sum of its proper divisors (68001413).

340007035 is an equidigital number, since it uses as much as digits as its factorization.

340007035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68001412.

The product of its (nonzero) digits is 1260, while the sum is 22.

The square root of 340007035 is about 18439.2796768204. The cubic root of 340007035 is about 697.9580184820.

Adding to 340007035 its reverse (530700043), we get a palindrome (870707078).

The spelling of 340007035 in words is "three hundred forty million, seven thousand, thirty-five".

Divisors: 1 5 68001407 340007035