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3400203111439 is a prime number
BaseRepresentation
bin110001011110101011111…
…001100000110000001111
3110001001112000000202221211
4301132223321200300033
5421202103444031224
611122010505035251
7500441126401531
oct61365371406017
913031460022854
103400203111439
1110a1022016772
1246ab95185b27
131b883a274814
14ba7dc04b851
155d6a8dad894
hex317abe60c0f

3400203111439 has 2 divisors, whose sum is σ = 3400203111440. Its totient is φ = 3400203111438.

The previous prime is 3400203111407. The next prime is 3400203111479. The reversal of 3400203111439 is 9341113020043.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3400203111439 - 25 = 3400203111407 is a prime.

It is a super-3 number, since 3×34002031114393 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 3400203111439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3400203111479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700101555719 + 1700101555720.

It is an arithmetic number, because the mean of its divisors is an integer number (1700101555720).

Almost surely, 23400203111439 is an apocalyptic number.

3400203111439 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400203111439 is an equidigital number, since it uses as much as digits as its factorization.

3400203111439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 3400203111439 in words is "three trillion, four hundred billion, two hundred three million, one hundred eleven thousand, four hundred thirty-nine".