Base | Representation |
---|---|
bin | 1111011101100101111000… |
… | …10111101001001110111111 |
3 | 11110101120102022020021012221 |
4 | 13232302330113221032333 |
5 | 13424042321041224301 |
6 | 200152205310510211 |
7 | 10106400160302313 |
oct | 756627427511677 |
9 | 143346368207187 |
10 | 34002121429951 |
11 | a91a245128414 |
12 | 3991a09805367 |
13 | 15c85038b9a7c |
14 | 8579d6353b43 |
15 | 3de717130da1 |
hex | 1eecbc5e93bf |
34002121429951 has 2 divisors, whose sum is σ = 34002121429952. Its totient is φ = 34002121429950.
The previous prime is 34002121429937. The next prime is 34002121430041. The reversal of 34002121429951 is 15992412120043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34002121429951 - 27 = 34002121429823 is a prime.
It is a super-2 number, since 2×340021214299512 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34002121429898 and 34002121429907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34002121420951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17001060714975 + 17001060714976.
It is an arithmetic number, because the mean of its divisors is an integer number (17001060714976).
Almost surely, 234002121429951 is an apocalyptic number.
34002121429951 is a deficient number, since it is larger than the sum of its proper divisors (1).
34002121429951 is an equidigital number, since it uses as much as digits as its factorization.
34002121429951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 43.
Adding to 34002121429951 its reverse (15992412120043), we get a palindrome (49994533549994).
The spelling of 34002121429951 in words is "thirty-four trillion, two billion, one hundred twenty-one million, four hundred twenty-nine thousand, nine hundred fifty-one".
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