Base | Representation |
---|---|
bin | 1111011101100101111000… |
… | …10111101001011100010011 |
3 | 11110101120102022020022101111 |
4 | 13232302330113221130103 |
5 | 13424042321041241203 |
6 | 200152205310514151 |
7 | 10106400160304641 |
oct | 756627427513423 |
9 | 143346368208344 |
10 | 34002121430803 |
11 | a91a245129019 |
12 | 3991a09805957 |
13 | 15c85038ba286 |
14 | 8579d6354191 |
15 | 3de71713126d |
hex | 1eecbc5e9713 |
34002121430803 has 2 divisors, whose sum is σ = 34002121430804. Its totient is φ = 34002121430802.
The previous prime is 34002121430789. The next prime is 34002121430843. The reversal of 34002121430803 is 30803412120043.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34002121430803 - 237 = 33864682477331 is a prime.
It is a super-2 number, since 2×340021214308032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34002121430843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17001060715401 + 17001060715402.
It is an arithmetic number, because the mean of its divisors is an integer number (17001060715402).
Almost surely, 234002121430803 is an apocalyptic number.
34002121430803 is a deficient number, since it is larger than the sum of its proper divisors (1).
34002121430803 is an equidigital number, since it uses as much as digits as its factorization.
34002121430803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 34002121430803 its reverse (30803412120043), we get a palindrome (64805533550846).
The spelling of 34002121430803 in words is "thirty-four trillion, two billion, one hundred twenty-one million, four hundred thirty thousand, eight hundred three".
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