Base | Representation |
---|---|
bin | 1111011101100110001111… |
… | …01100000001000111101011 |
3 | 11110101120220112112200110022 |
4 | 13232303013230001013223 |
5 | 13424043213144220133 |
6 | 200152240212511055 |
7 | 10106404654321613 |
oct | 756630754010753 |
9 | 143346815480408 |
10 | 34002311320043 |
11 | a91a332335680 |
12 | 3991a6131b48b |
13 | 15c8534044481 |
14 | 857a13663a43 |
15 | 3de728b3e998 |
hex | 1eecc7b011eb |
34002311320043 has 16 divisors (see below), whose sum is σ = 38744098751232. Its totient is φ = 29538267924000.
The previous prime is 34002311320031. The next prime is 34002311320057.
34002311320043 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 34002311320043 - 210 = 34002311319019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34002311319994 and 34002311320021.
It is not an unprimeable number, because it can be changed into a prime (34002311328043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65557793 + ... + 66074418.
It is an arithmetic number, because the mean of its divisors is an integer number (2421506171952).
Almost surely, 234002311320043 is an apocalyptic number.
34002311320043 is a deficient number, since it is larger than the sum of its proper divisors (4741787431189).
34002311320043 is a wasteful number, since it uses less digits than its factorization.
34002311320043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131633266.
The product of its (nonzero) digits is 5184, while the sum is 26.
It can be divided in two parts, 3400231 and 1320043, that added together give a palindrome (4720274).
The spelling of 34002311320043 in words is "thirty-four trillion, two billion, three hundred eleven million, three hundred twenty thousand, forty-three".
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