Base | Representation |
---|---|
bin | 100110101010000000000100… |
… | …0011000000011011011111101 |
3 | 1122120220222122221202021202111 |
4 | 1031110000020120003123331 |
5 | 324031423340010203424 |
6 | 3203100530443454021 |
7 | 131422634313262363 |
oct | 11524001030033375 |
9 | 1576828587667674 |
10 | 340024111412989 |
11 | 99384463533a93 |
12 | 32176b4ab27311 |
13 | 117961a00a7153 |
14 | 5dd737d26d633 |
15 | 2949c1a228194 |
hex | 13540086036fd |
340024111412989 has 2 divisors, whose sum is σ = 340024111412990. Its totient is φ = 340024111412988.
The previous prime is 340024111412939. The next prime is 340024111413023. The reversal of 340024111412989 is 989214111420043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 255032915062500 + 84991196350489 = 15969750^2 + 9219067^2 .
It is a cyclic number.
It is not a de Polignac number, because 340024111412989 - 213 = 340024111404797 is a prime.
It is a super-2 number, since 2×3400241114129892 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340024111412939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170012055706494 + 170012055706495.
It is an arithmetic number, because the mean of its divisors is an integer number (170012055706495).
Almost surely, 2340024111412989 is an apocalyptic number.
It is an amenable number.
340024111412989 is a deficient number, since it is larger than the sum of its proper divisors (1).
340024111412989 is an equidigital number, since it uses as much as digits as its factorization.
340024111412989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 49.
The spelling of 340024111412989 in words is "three hundred forty trillion, twenty-four billion, one hundred eleven million, four hundred twelve thousand, nine hundred eighty-nine".
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