Base | Representation |
---|---|
bin | 100110101010000000100100… |
… | …1100001100011001001011011 |
3 | 1122120221002111010102212011111 |
4 | 1031110001021201203021123 |
5 | 324031433104312434321 |
6 | 3203101231130441151 |
7 | 131423003354555311 |
oct | 11524011141431133 |
9 | 1576832433385144 |
10 | 340025204421211 |
11 | 99384974503271 |
12 | 321771b4b931b7 |
13 | 1179631567a58a |
14 | 5dd74444ac0b1 |
15 | 2949c8117c5e1 |
hex | 135404986325b |
340025204421211 has 4 divisors (see below), whose sum is σ = 340025269691800. Its totient is φ = 340025139150624.
The previous prime is 340025204421143. The next prime is 340025204421281. The reversal of 340025204421211 is 112124402520043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 340025204421211 - 217 = 340025204290139 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340025204421281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24072126 + ... + 35489683.
It is an arithmetic number, because the mean of its divisors is an integer number (85006317422950).
Almost surely, 2340025204421211 is an apocalyptic number.
340025204421211 is a deficient number, since it is larger than the sum of its proper divisors (65270589).
340025204421211 is an equidigital number, since it uses as much as digits as its factorization.
340025204421211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65270588.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 340025204421211 its reverse (112124402520043), we get a palindrome (452149606941254).
The spelling of 340025204421211 in words is "three hundred forty trillion, twenty-five billion, two hundred four million, four hundred twenty-one thousand, two hundred eleven".
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