112124402520043 has 4 divisors (see below), whose sum is σ = 112127838473448. Its totient is φ = 112120966566640.

The previous prime is 112124402520019. The next prime is 112124402520061. The reversal of 112124402520043 is 340025204421211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112124402520043 - 2²¹ = 112124400422891 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112124402519987 and 112124402520014.

It is not an unprimeable number, because it can be changed into a prime (112124402220043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1717927753 + ... + 1717993018.

It is an arithmetic number, because the mean of its divisors is an integer number (28031959618362).

Almost surely, 2^{112124402520043} is an apocalyptic number.

112124402520043 is a deficient number, since it is larger than the sum of its proper divisors (3435953405).

112124402520043 is an equidigital number, since it uses as much as digits as its factorization.

112124402520043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3435953404.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 112124402520043 its reverse (340025204421211), we get a palindrome (452149606941254).

The spelling of 112124402520043 in words is "one hundred twelve trillion, one hundred twenty-four billion, four hundred two million, five hundred twenty thousand, forty-three".