340031135401 has 4 divisors (see below), whose sum is σ = 340039157904. Its totient is φ = 340023112900.

The previous prime is 340031135369. The next prime is 340031135429. The reversal of 340031135401 is 104531130043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 340031135401 - 2⁵ = 340031135369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340031135441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3947335 + ... + 4032556.

It is an arithmetic number, because the mean of its divisors is an integer number (85009789476).

Almost surely, 2^340031135401 is an apocalyptic number.

It is an amenable number.

340031135401 is a deficient number, since it is larger than the sum of its proper divisors (8022503).

340031135401 is an equidigital number, since it uses as much as digits as its factorization.

340031135401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8022502.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 340031135401 its reverse (104531130043), we get a palindrome (444562265444).

The spelling of 340031135401 in words is "three hundred forty billion, thirty-one million, one hundred thirty-five thousand, four hundred one".