Base | Representation |
---|---|
bin | 1001111001010111000… |
… | …01000110011001010011 |
3 | 1012111200110011102112201 |
4 | 10330223201012121103 |
5 | 21032341310413434 |
6 | 420113032504031 |
7 | 33365215451131 |
oct | 4745341063123 |
9 | 1174613142481 |
10 | 340032513619 |
11 | 1212305422a7 |
12 | 55a9824b017 |
13 | 260ac8562a6 |
14 | 12659b74751 |
15 | 8ca1e69614 |
hex | 4f2b846653 |
340032513619 has 2 divisors, whose sum is σ = 340032513620. Its totient is φ = 340032513618.
The previous prime is 340032513551. The next prime is 340032513629. The reversal of 340032513619 is 916315230043.
It is a strong prime.
It is an emirp because it is prime and its reverse (916315230043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 340032513619 - 225 = 339998959187 is a prime.
It is a super-2 number, since 2×3400325136192 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (340032513629) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170016256809 + 170016256810.
It is an arithmetic number, because the mean of its divisors is an integer number (170016256810).
Almost surely, 2340032513619 is an apocalyptic number.
340032513619 is a deficient number, since it is larger than the sum of its proper divisors (1).
340032513619 is an equidigital number, since it uses as much as digits as its factorization.
340032513619 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 340032513619 in words is "three hundred forty billion, thirty-two million, five hundred thirteen thousand, six hundred nineteen".
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