Base | Representation |
---|---|
bin | 1001111001010111000… |
… | …01000110011000001111 |
3 | 1012111200110011102110012 |
4 | 10330223201012120033 |
5 | 21032341310413201 |
6 | 420113032503435 |
7 | 33365215451003 |
oct | 4745341063017 |
9 | 1174613142405 |
10 | 340032513551 |
11 | 121230542245 |
12 | 55a9824ab7b |
13 | 260ac856253 |
14 | 12659b74703 |
15 | 8ca1e695bb |
hex | 4f2b84660f |
340032513551 has 2 divisors, whose sum is σ = 340032513552. Its totient is φ = 340032513550.
The previous prime is 340032513547. The next prime is 340032513619. The reversal of 340032513551 is 155315230043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 340032513551 - 22 = 340032513547 is a prime.
It is a super-3 number, since 3×3400325135513 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340032513511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170016256775 + 170016256776.
It is an arithmetic number, because the mean of its divisors is an integer number (170016256776).
Almost surely, 2340032513551 is an apocalyptic number.
340032513551 is a deficient number, since it is larger than the sum of its proper divisors (1).
340032513551 is an equidigital number, since it uses as much as digits as its factorization.
340032513551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 340032513551 its reverse (155315230043), we get a palindrome (495347743594).
The spelling of 340032513551 in words is "three hundred forty billion, thirty-two million, five hundred thirteen thousand, five hundred fifty-one".
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