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3400367000053 is a prime number
BaseRepresentation
bin110001011110110101101…
…010101100100111110101
3110001001221102102011212111
4301132311222230213311
5421202422423000203
611122035041451021
7500445156415102
oct61366552544765
913031842364774
103400367000053
1110a10a6584701
1246b020040a71
131b88651c722a
14ba815b0daa9
155d6b848326d
hex317b5aac9f5

3400367000053 has 2 divisors, whose sum is σ = 3400367000054. Its totient is φ = 3400367000052.

The previous prime is 3400367000027. The next prime is 3400367000059. The reversal of 3400367000053 is 3500007630043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3349804081009 + 50562919044 = 1830247^2 + 224862^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3400367000053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3400366999979 and 3400367000024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3400367000059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700183500026 + 1700183500027.

It is an arithmetic number, because the mean of its divisors is an integer number (1700183500027).

Almost surely, 23400367000053 is an apocalyptic number.

It is an amenable number.

3400367000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400367000053 is an equidigital number, since it uses as much as digits as its factorization.

3400367000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22680, while the sum is 31.

The spelling of 3400367000053 in words is "three trillion, four hundred billion, three hundred sixty-seven million, fifty-three", and thus it is an aban number.