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340043320123 = 1326157178471
BaseRepresentation
bin1001111001011000010…
…10010100101100111011
31012111201012111110021121
410330230022110230323
521032402042220443
6420114100250111
733365406350023
oct4745412245473
91174635443247
10340043320123
111212366533a1
1255a9b9a0937
13260b1b6ac80
141265b388a83
158ca2da14ed
hex4f2c294b3b

340043320123 has 4 divisors (see below), whose sum is σ = 366200498608. Its totient is φ = 313886141640.

The previous prime is 340043320109. The next prime is 340043320147. The reversal of 340043320123 is 321023340043.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 321023340043 = 745860477149.

It is a cyclic number.

It is not a de Polignac number, because 340043320123 - 213 = 340043311931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340043320223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13078589223 + ... + 13078589248.

It is an arithmetic number, because the mean of its divisors is an integer number (91550124652).

Almost surely, 2340043320123 is an apocalyptic number.

340043320123 is a deficient number, since it is larger than the sum of its proper divisors (26157178485).

340043320123 is a wasteful number, since it uses less digits than its factorization.

340043320123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26157178484.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 340043320123 its reverse (321023340043), we get a palindrome (661066660166).

The spelling of 340043320123 in words is "three hundred forty billion, forty-three million, three hundred twenty thousand, one hundred twenty-three".

Divisors: 1 13 26157178471 340043320123