Base | Representation |
---|---|
bin | 110001011110111101100… |
… | …110001111101001100101 |
3 | 110001002021200202211211001 |
4 | 301132331212033221211 |
5 | 421203211003104113 |
6 | 11122100153313301 |
7 | 500451363342265 |
oct | 61367546175145 |
9 | 13032250684731 |
10 | 3400500050533 |
11 | 10a116469a483 |
12 | 46b058705831 |
13 | 1b8886940321 |
14 | ba8296657a5 |
15 | 5d6c4eb57dd |
hex | 317bd98fa65 |
3400500050533 has 2 divisors, whose sum is σ = 3400500050534. Its totient is φ = 3400500050532.
The previous prime is 3400500050503. The next prime is 3400500050573. The reversal of 3400500050533 is 3350500050043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3337077672289 + 63422378244 = 1826767^2 + 251838^2 .
It is a cyclic number.
It is not a de Polignac number, because 3400500050533 - 25 = 3400500050501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3400500050503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700250025266 + 1700250025267.
It is an arithmetic number, because the mean of its divisors is an integer number (1700250025267).
Almost surely, 23400500050533 is an apocalyptic number.
It is an amenable number.
3400500050533 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400500050533 is an equidigital number, since it uses as much as digits as its factorization.
3400500050533 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 28.
The spelling of 3400500050533 in words is "three trillion, four hundred billion, five hundred million, fifty thousand, five hundred thirty-three".
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