Base | Representation |
---|---|
bin | 100110101010100011011101… |
… | …0111011010001001110101011 |
3 | 1122121012020212020000101011221 |
4 | 1031111012322323101032223 |
5 | 324034200022041324003 |
6 | 3203155501110202511 |
7 | 131431265025632311 |
oct | 11525067273211653 |
9 | 1577166766011157 |
10 | 340100121433003 |
11 | 99403719180048 |
12 | 32189822653437 |
13 | 117a03c46b8259 |
14 | 5ddad101420b1 |
15 | 294bbb82a07bd |
hex | 13551baed13ab |
340100121433003 has 8 divisors (see below), whose sum is σ = 360106241212080. Its totient is φ = 320094027240960.
The previous prime is 340100121433001. The next prime is 340100121433057. The reversal of 340100121433003 is 300334121001043.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 340100121433003 - 21 = 340100121433001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340100121433001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25518508 + ... + 36488278.
It is an arithmetic number, because the mean of its divisors is an integer number (45013280151510).
Almost surely, 2340100121433003 is an apocalyptic number.
340100121433003 is a deficient number, since it is larger than the sum of its proper divisors (20006119779077).
340100121433003 is a wasteful number, since it uses less digits than its factorization.
340100121433003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12793517.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 340100121433003 its reverse (300334121001043), we get a palindrome (640434242434046).
The spelling of 340100121433003 in words is "three hundred forty trillion, one hundred billion, one hundred twenty-one million, four hundred thirty-three thousand, three".
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