Base | Representation |
---|---|
bin | 110001011111100010100… |
… | …011101000011000110111 |
3 | 110001010212220112202112121 |
4 | 301133202203220120313 |
5 | 421210443222404143 |
6 | 11122241503500411 |
7 | 500502633020122 |
oct | 61374243503067 |
9 | 13033786482477 |
10 | 3401120122423 |
11 | 10a1452707691 |
12 | 46b1b02b7707 |
13 | 1b8955245c7a |
14 | ba887b553b9 |
15 | 5d70e64a7ed |
hex | 317e28e8637 |
3401120122423 has 2 divisors, whose sum is σ = 3401120122424. Its totient is φ = 3401120122422.
The previous prime is 3401120122373. The next prime is 3401120122429. The reversal of 3401120122423 is 3242210211043.
It is a strong prime.
It is an emirp because it is prime and its reverse (3242210211043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3401120122423 - 217 = 3401119991351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3401120122429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700560061211 + 1700560061212.
It is an arithmetic number, because the mean of its divisors is an integer number (1700560061212).
Almost surely, 23401120122423 is an apocalyptic number.
3401120122423 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401120122423 is an equidigital number, since it uses as much as digits as its factorization.
3401120122423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3401120122423 its reverse (3242210211043), we get a palindrome (6643330333466).
The spelling of 3401120122423 in words is "three trillion, four hundred one billion, one hundred twenty million, one hundred twenty-two thousand, four hundred twenty-three".
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