Base | Representation |
---|---|
bin | 110001011111100011010… |
… | …001011100011111010111 |
3 | 110001010220202010221000021 |
4 | 301133203101130133113 |
5 | 421211004311213221 |
6 | 11122243013130011 |
7 | 500503140060304 |
oct | 61374321343727 |
9 | 13033822127007 |
10 | 3401132132311 |
11 | 10a145946a911 |
12 | 46b1b4329907 |
13 | 1b895788c604 |
14 | ba8895a00ab |
15 | 5d71071e041 |
hex | 317e345c7d7 |
3401132132311 has 2 divisors, whose sum is σ = 3401132132312. Its totient is φ = 3401132132310.
The previous prime is 3401132132303. The next prime is 3401132132329. The reversal of 3401132132311 is 1132312311043.
It is a weak prime.
It is an emirp because it is prime and its reverse (1132312311043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3401132132311 - 23 = 3401132132303 is a prime.
It is a super-2 number, since 2×34011321323112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3401132132341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700566066155 + 1700566066156.
It is an arithmetic number, because the mean of its divisors is an integer number (1700566066156).
Almost surely, 23401132132311 is an apocalyptic number.
3401132132311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401132132311 is an equidigital number, since it uses as much as digits as its factorization.
3401132132311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 3401132132311 its reverse (1132312311043), we get a palindrome (4533444443354).
The spelling of 3401132132311 in words is "three trillion, four hundred one billion, one hundred thirty-two million, one hundred thirty-two thousand, three hundred eleven".
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