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340114125173 is a prime number
BaseRepresentation
bin1001111001100000110…
…00011011000101110101
31012111220010201201112212
410330300120123011311
521033023204001143
6420125110023205
733400226235524
oct4746030330565
91174803651485
10340114125173
11121272614269
1255abb647b05
13260c372c054
141266693a4bb
158ca91da918
hex4f3061b175

340114125173 has 2 divisors, whose sum is σ = 340114125174. Its totient is φ = 340114125172.

The previous prime is 340114125119. The next prime is 340114125179. The reversal of 340114125173 is 371521411043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 331491517009 + 8622608164 = 575753^2 + 92858^2 .

It is an emirp because it is prime and its reverse (371521411043) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-340114125173 is a prime.

It is a super-2 number, since 2×3401141251732 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (340114125179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170057062586 + 170057062587.

It is an arithmetic number, because the mean of its divisors is an integer number (170057062587).

Almost surely, 2340114125173 is an apocalyptic number.

It is an amenable number.

340114125173 is a deficient number, since it is larger than the sum of its proper divisors (1).

340114125173 is an equidigital number, since it uses as much as digits as its factorization.

340114125173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

The spelling of 340114125173 in words is "three hundred forty billion, one hundred fourteen million, one hundred twenty-five thousand, one hundred seventy-three".