Base | Representation |
---|---|
bin | 11111101011010011… |
… | …000011101001010111 |
3 | 10020210101100120120121 |
4 | 133223103003221113 |
5 | 1024124134200003 |
6 | 23343004012411 |
7 | 2312600510326 |
oct | 375323035127 |
9 | 106711316517 |
10 | 34012412503 |
11 | 13474135a23 |
12 | 6712831107 |
13 | 3290741494 |
14 | 19092b00bd |
15 | d41001cbd |
hex | 7eb4c3a57 |
34012412503 has 2 divisors, whose sum is σ = 34012412504. Its totient is φ = 34012412502.
The previous prime is 34012412471. The next prime is 34012412531. The reversal of 34012412503 is 30521421043.
It is a strong prime.
It is an emirp because it is prime and its reverse (30521421043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34012412503 - 25 = 34012412471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34012412573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17006206251 + 17006206252.
It is an arithmetic number, because the mean of its divisors is an integer number (17006206252).
Almost surely, 234012412503 is an apocalyptic number.
34012412503 is a deficient number, since it is larger than the sum of its proper divisors (1).
34012412503 is an equidigital number, since it uses as much as digits as its factorization.
34012412503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 34012412503 its reverse (30521421043), we get a palindrome (64533833546).
The spelling of 34012412503 in words is "thirty-four billion, twelve million, four hundred twelve thousand, five hundred three".
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