34013100431333 has 4 divisors (see below), whose sum is σ = 34479033314028. Its totient is φ = 33547167548640.

The previous prime is 34013100431327. The next prime is 34013100431413. The reversal of 34013100431333 is 33313400131043.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13609296490084 + 20403803941249 = 3689078^2 + 4517057^2 .

It is a cyclic number.

It is not a de Polignac number, because 34013100431333 - 2¹² = 34013100427237 is a prime.

It is a super-2 number, since 2×34013100431333² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34013100431296 and 34013100431305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34013100437333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232966441238 + ... + 232966441383.

It is an arithmetic number, because the mean of its divisors is an integer number (8619758328507).

Almost surely, 2^{34013100431333} is an apocalyptic number.

It is an amenable number.

34013100431333 is a deficient number, since it is larger than the sum of its proper divisors (465932882695).

34013100431333 is an equidigital number, since it uses as much as digits as its factorization.

34013100431333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465932882694.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 34013100431333 its reverse (33313400131043), we get a palindrome (67326500562376).

The spelling of 34013100431333 in words is "thirty-four trillion, thirteen billion, one hundred million, four hundred thirty-one thousand, three hundred thirty-three".