Base | Representation |
---|---|
bin | 1001111001100100010… |
… | …00101011011000010001 |
3 | 1012111222012002202120222 |
4 | 10330302020223120101 |
5 | 21033103222131032 |
6 | 420132040442425 |
7 | 33401034326213 |
oct | 4746210533021 |
9 | 1174865082528 |
10 | 340143552017 |
11 | 121288193075 |
12 | 55b09479415 |
13 | 260c9863199 |
14 | 1266a7da5b3 |
15 | 8caba9ea12 |
hex | 4f3222b611 |
340143552017 has 2 divisors, whose sum is σ = 340143552018. Its totient is φ = 340143552016.
The previous prime is 340143552013. The next prime is 340143552113. The reversal of 340143552017 is 710255341043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 338775217936 + 1368334081 = 582044^2 + 36991^2 .
It is an emirp because it is prime and its reverse (710255341043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 340143552017 - 22 = 340143552013 is a prime.
It is not a weakly prime, because it can be changed into another prime (340143552013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170071776008 + 170071776009.
It is an arithmetic number, because the mean of its divisors is an integer number (170071776009).
Almost surely, 2340143552017 is an apocalyptic number.
It is an amenable number.
340143552017 is a deficient number, since it is larger than the sum of its proper divisors (1).
340143552017 is an equidigital number, since it uses as much as digits as its factorization.
340143552017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 340143552017 in words is "three hundred forty billion, one hundred forty-three million, five hundred fifty-two thousand, seventeen".
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