Base | Representation |
---|---|
bin | 110001100000010111000… |
… | …000100110111110001001 |
3 | 110001020011020102222111220 |
4 | 301200113000212332021 |
5 | 421214244013242100 |
6 | 11122505101312253 |
7 | 500533510005453 |
oct | 61402700467611 |
9 | 13036136388456 |
10 | 3402000134025 |
11 | 10a18644273a9 |
12 | 46b3b6b65689 |
13 | 1b8a656615ac |
14 | ba92c98b2d3 |
15 | 5d761a29aa0 |
hex | 31817026f89 |
3402000134025 has 48 divisors (see below), whose sum is σ = 5884418873088. Its totient is φ = 1732483648000.
The previous prime is 3402000134009. The next prime is 3402000134051. The reversal of 3402000134025 is 5204310002043.
It is not a de Polignac number, because 3402000134025 - 24 = 3402000134009 is a prime.
It is a super-2 number, since 2×34020001340252 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3402000133986 and 3402000134004.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11625066 + ... + 11914115.
It is an arithmetic number, because the mean of its divisors is an integer number (122592059856).
Almost surely, 23402000134025 is an apocalyptic number.
It is an amenable number.
3402000134025 is a deficient number, since it is larger than the sum of its proper divisors (2482418739063).
3402000134025 is a wasteful number, since it uses less digits than its factorization.
3402000134025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23539282 (or 23539277 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 3402000134025 its reverse (5204310002043), we get a palindrome (8606310136068).
The spelling of 3402000134025 in words is "three trillion, four hundred two billion, one hundred thirty-four thousand, twenty-five".
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