Base | Representation |
---|---|
bin | 110001100000010111000… |
… | …000100110111110100011 |
3 | 110001020011020102222112212 |
4 | 301200113000212332203 |
5 | 421214244013242201 |
6 | 11122505101312335 |
7 | 500533510005521 |
oct | 61402700467643 |
9 | 13036136388485 |
10 | 3402000134051 |
11 | 10a1864427422 |
12 | 46b3b6b656ab |
13 | 1b8a656615cc |
14 | ba92c98b311 |
15 | 5d761a29abb |
hex | 31817026fa3 |
3402000134051 has 2 divisors, whose sum is σ = 3402000134052. Its totient is φ = 3402000134050.
The previous prime is 3402000134009. The next prime is 3402000134059. The reversal of 3402000134051 is 1504310002043.
3402000134051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3402000134051 - 214 = 3402000117667 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (3402000134059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1701000067025 + 1701000067026.
It is an arithmetic number, because the mean of its divisors is an integer number (1701000067026).
Almost surely, 23402000134051 is an apocalyptic number.
3402000134051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3402000134051 is an equidigital number, since it uses as much as digits as its factorization.
3402000134051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 3402000134051 its reverse (1504310002043), we get a palindrome (4906310136094).
The spelling of 3402000134051 in words is "three trillion, four hundred two billion, one hundred thirty-four thousand, fifty-one".
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