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340210113423449 is a prime number
BaseRepresentation
bin100110101011010110101011…
…0111101011010100001011001
31122121120202202202100102111212
41031112231112331122201121
5324043000303014022244
63203322211332232505
7131442240522263303
oct11526552675324131
91577522682312455
10340210113423449
119944633184a495
12321a6bba76b735
13117aa8a333c579
14600238623c973
15294e9a4814d9e
hex1356b56f5a859

340210113423449 has 2 divisors, whose sum is σ = 340210113423450. Its totient is φ = 340210113423448.

The previous prime is 340210113423419. The next prime is 340210113423451. The reversal of 340210113423449 is 944324311012043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 308939257982224 + 31270855441225 = 17576668^2 + 5592035^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-340210113423449 is a prime.

Together with 340210113423451, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (340210113423419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170105056711724 + 170105056711725.

It is an arithmetic number, because the mean of its divisors is an integer number (170105056711725).

Almost surely, 2340210113423449 is an apocalyptic number.

It is an amenable number.

340210113423449 is a deficient number, since it is larger than the sum of its proper divisors (1).

340210113423449 is an equidigital number, since it uses as much as digits as its factorization.

340210113423449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 41.

The spelling of 340210113423449 in words is "three hundred forty trillion, two hundred ten billion, one hundred thirteen million, four hundred twenty-three thousand, four hundred forty-nine".