Base | Representation |
---|---|
bin | 100110101011011011011100… |
… | …0000111010011011100010001 |
3 | 1122121121202010222221000000201 |
4 | 1031112312320013103130101 |
5 | 324043132220313343213 |
6 | 3203331021412415201 |
7 | 131443052010164530 |
oct | 11526667007233421 |
9 | 1577552128830021 |
10 | 340220333340433 |
11 | 9944a6a6710377 |
12 | 321a8b91317501 |
13 | 117ab841768720 |
14 | 6002a7568a317 |
15 | 294eda1b636dd |
hex | 1356db81d3711 |
340220333340433 has 32 divisors (see below), whose sum is σ = 449087721465600. Its totient is φ = 250206016110336.
The previous prime is 340220333340373. The next prime is 340220333340439. The reversal of 340220333340433 is 334043333022043.
It is a de Polignac number, because none of the positive numbers 2k-340220333340433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 340220333340392 and 340220333340401.
It is not an unprimeable number, because it can be changed into a prime (340220333340439) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1856256418 + ... + 1856439691.
It is an arithmetic number, because the mean of its divisors is an integer number (14033991295800).
Almost surely, 2340220333340433 is an apocalyptic number.
It is an amenable number.
340220333340433 is a deficient number, since it is larger than the sum of its proper divisors (108867388125167).
340220333340433 is a wasteful number, since it uses less digits than its factorization.
340220333340433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3712696201.
The product of its (nonzero) digits is 559872, while the sum is 37.
Adding to 340220333340433 its reverse (334043333022043), we get a palindrome (674263666362476).
The spelling of 340220333340433 in words is "three hundred forty trillion, two hundred twenty billion, three hundred thirty-three million, three hundred forty thousand, four hundred thirty-three".
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