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3402269138447 is a prime number
BaseRepresentation
bin110001100000100111000…
…010110001111000001111
3110001020211222121211012122
4301200213002301320033
5421220321344412242
611122551511123155
7500543254342064
oct61404702617017
913036758554178
103402269138447
1110a1992260403
1246b4710734bb
131b8aa92c91ca
14ba9565b2c6b
155d77a464ad2
hex318270b1e0f

3402269138447 has 2 divisors, whose sum is σ = 3402269138448. Its totient is φ = 3402269138446.

The previous prime is 3402269138419. The next prime is 3402269138467. The reversal of 3402269138447 is 7448319622043.

It is a strong prime.

It is an emirp because it is prime and its reverse (7448319622043) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3402269138447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3402269138407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1701134569223 + 1701134569224.

It is an arithmetic number, because the mean of its divisors is an integer number (1701134569224).

Almost surely, 23402269138447 is an apocalyptic number.

3402269138447 is a deficient number, since it is larger than the sum of its proper divisors (1).

3402269138447 is an equidigital number, since it uses as much as digits as its factorization.

3402269138447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6967296, while the sum is 53.

The spelling of 3402269138447 in words is "three trillion, four hundred two billion, two hundred sixty-nine million, one hundred thirty-eight thousand, four hundred forty-seven".