Base | Representation |
---|---|
bin | 110001100001010101111… |
… | …001111010011010010101 |
3 | 110001022212210000011110011 |
4 | 301201111321322122111 |
5 | 421223424131441003 |
6 | 11123201514200221 |
7 | 500601612101266 |
oct | 61412571723225 |
9 | 13038783004404 |
10 | 3403055343253 |
11 | 10a2256029745 |
12 | 46b650423071 |
13 | 1b8ba315bc57 |
14 | ba9ccb8a96d |
15 | 5d7c44b446d |
hex | 31855e7a695 |
3403055343253 has 2 divisors, whose sum is σ = 3403055343254. Its totient is φ = 3403055343252.
The previous prime is 3403055343239. The next prime is 3403055343271. The reversal of 3403055343253 is 3523435503043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1909766455249 + 1493288888004 = 1381943^2 + 1222002^2 .
It is a cyclic number.
It is not a de Polignac number, because 3403055343253 - 213 = 3403055335061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3403055343283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1701527671626 + 1701527671627.
It is an arithmetic number, because the mean of its divisors is an integer number (1701527671627).
Almost surely, 23403055343253 is an apocalyptic number.
It is an amenable number.
3403055343253 is a deficient number, since it is larger than the sum of its proper divisors (1).
3403055343253 is an equidigital number, since it uses as much as digits as its factorization.
3403055343253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 40.
The spelling of 3403055343253 in words is "three trillion, four hundred three billion, fifty-five million, three hundred forty-three thousand, two hundred fifty-three".
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