Base | Representation |
---|---|
bin | 11111101100011010… |
… | …111001000010010101 |
3 | 10020211200210021201201 |
4 | 133230122321002111 |
5 | 1024143444242123 |
6 | 23344515352501 |
7 | 2313216540046 |
oct | 375432710225 |
9 | 106750707651 |
10 | 34031243413 |
11 | 13483827962 |
12 | 6718bb2731 |
13 | 329460572b |
14 | 190b9b28cd |
15 | d429c15ad |
hex | 7ec6b9095 |
34031243413 has 4 divisors (see below), whose sum is σ = 34037174848. Its totient is φ = 34025311980.
The previous prime is 34031243299. The next prime is 34031243429. The reversal of 34031243413 is 31434213043.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34031243413 - 29 = 34031242901 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34031243453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2957103 + ... + 2968588.
It is an arithmetic number, because the mean of its divisors is an integer number (8509293712).
Almost surely, 234031243413 is an apocalyptic number.
It is an amenable number.
34031243413 is a deficient number, since it is larger than the sum of its proper divisors (5931435).
34031243413 is an equidigital number, since it uses as much as digits as its factorization.
34031243413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5931434.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 34031243413 its reverse (31434213043), we get a palindrome (65465456456).
The spelling of 34031243413 in words is "thirty-four billion, thirty-one million, two hundred forty-three thousand, four hundred thirteen".
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