Base | Representation |
---|---|
bin | 1111011110011100011111… |
… | …00000011110011100010001 |
3 | 11110111101002010010210220001 |
4 | 13233032033200132130101 |
5 | 13430032333441311033 |
6 | 200213454051050001 |
7 | 10111455435162211 |
oct | 757161740363421 |
9 | 143441063123801 |
10 | 34031433541393 |
11 | a930717044602 |
12 | 399762a2a0901 |
13 | 15cb1c55c3402 |
14 | 8591b7298241 |
15 | 3e038067ae7d |
hex | 1ef38f81e711 |
34031433541393 has 2 divisors, whose sum is σ = 34031433541394. Its totient is φ = 34031433541392.
The previous prime is 34031433541381. The next prime is 34031433541403. The reversal of 34031433541393 is 39314533413043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25577365563649 + 8454067977744 = 5057407^2 + 2907588^2 .
It is a cyclic number.
It is not a de Polignac number, because 34031433541393 - 25 = 34031433541361 is a prime.
It is not a weakly prime, because it can be changed into another prime (34031433541373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17015716770696 + 17015716770697.
It is an arithmetic number, because the mean of its divisors is an integer number (17015716770697).
Almost surely, 234031433541393 is an apocalyptic number.
It is an amenable number.
34031433541393 is a deficient number, since it is larger than the sum of its proper divisors (1).
34031433541393 is an equidigital number, since it uses as much as digits as its factorization.
34031433541393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2099520, while the sum is 46.
The spelling of 34031433541393 in words is "thirty-four trillion, thirty-one billion, four hundred thirty-three million, five hundred forty-one thousand, three hundred ninety-three".
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