Base | Representation |
---|---|
bin | 110001100010010000110… |
… | …110111111001110110111 |
3 | 110001102102201011002120020 |
4 | 301202100312333032313 |
5 | 421232440333313221 |
6 | 11123444005540223 |
7 | 500635252156665 |
oct | 61422066771667 |
9 | 13042381132506 |
10 | 3404044432311 |
11 | 10a271337aa16 |
12 | 46b887714673 |
13 | 1b9000048a53 |
14 | baa84297c35 |
15 | 5d83123cac6 |
hex | 31890dbf3b7 |
3404044432311 has 16 divisors (see below), whose sum is σ = 4807543516128. Its totient is φ = 2135056025600.
The previous prime is 3404044432289. The next prime is 3404044432331. The reversal of 3404044432311 is 1132344404043.
It is a cyclic number.
It is not a de Polignac number, because 3404044432311 - 27 = 3404044432183 is a prime.
It is a super-3 number, since 3×34040444323113 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3404044432331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12599250 + ... + 12866591.
It is an arithmetic number, because the mean of its divisors is an integer number (300471469758).
Almost surely, 23404044432311 is an apocalyptic number.
3404044432311 is a deficient number, since it is larger than the sum of its proper divisors (1403499083817).
3404044432311 is a wasteful number, since it uses less digits than its factorization.
3404044432311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25468482.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 3404044432311 its reverse (1132344404043), we get a palindrome (4536388836354).
The spelling of 3404044432311 in words is "three trillion, four hundred four billion, forty-four million, four hundred thirty-two thousand, three hundred eleven".
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