Base | Representation |
---|---|
bin | 100110101100110001011111… |
… | …0011000100011101111000101 |
3 | 1122122021102010020121122202110 |
4 | 1031121202332120203233011 |
5 | 324104144142230330040 |
6 | 3203551542041331233 |
7 | 131462313154665141 |
oct | 11531427630435705 |
9 | 1578242106548673 |
10 | 340405122120645 |
11 | 99511002103a4a |
12 | 32218962796b19 |
13 | 117c30b055671a |
14 | 600b9a5484221 |
15 | 2954ab999e980 |
hex | 13598be623bc5 |
340405122120645 has 32 divisors (see below), whose sum is σ = 544978583195904. Its totient is φ = 181439284608000.
The previous prime is 340405122120551. The next prime is 340405122120697. The reversal of 340405122120645 is 546021221504043.
It is not a de Polignac number, because 340405122120645 - 229 = 340404585249733 is a prime.
It is a super-3 number, since 3×3404051221206453 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 358329885 + ... + 359278605.
It is an arithmetic number, because the mean of its divisors is an integer number (17030580724872).
Almost surely, 2340405122120645 is an apocalyptic number.
It is an amenable number.
340405122120645 is a deficient number, since it is larger than the sum of its proper divisors (204573461075259).
340405122120645 is a wasteful number, since it uses less digits than its factorization.
340405122120645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 963213.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 340405122120645 its reverse (546021221504043), we get a palindrome (886426343624688).
The spelling of 340405122120645 in words is "three hundred forty trillion, four hundred five billion, one hundred twenty-two million, one hundred twenty thousand, six hundred forty-five".
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