Base | Representation |
---|---|
bin | 110001100010010001011… |
… | …000010000010111001001 |
3 | 110001102110022120011102001 |
4 | 301202101120100113021 |
5 | 421233000101400400 |
6 | 11123444520511001 |
7 | 500635416251254 |
oct | 61422130202711 |
9 | 13042408504361 |
10 | 3404053153225 |
11 | 10a271829708a |
12 | 46b88a61b461 |
13 | 1b9001ab035a |
14 | baa854c809b |
15 | 5d831db1a6a |
hex | 318916105c9 |
3404053153225 has 12 divisors (see below), whose sum is σ = 4443185169040. Its totient is φ = 2579913968400.
The previous prime is 3404053153213. The next prime is 3404053153247. The reversal of 3404053153225 is 5223513504043.
It is a de Polignac number, because none of the positive numbers 2k-3404053153225 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3583213371 + ... + 3583214320.
Almost surely, 23404053153225 is an apocalyptic number.
It is an amenable number.
3404053153225 is a deficient number, since it is larger than the sum of its proper divisors (1039132015815).
3404053153225 is a wasteful number, since it uses less digits than its factorization.
3404053153225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7166427720 (or 7166427715 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 3404053153225 its reverse (5223513504043), we get a palindrome (8627566657268).
The spelling of 3404053153225 in words is "three trillion, four hundred four billion, fifty-three million, one hundred fifty-three thousand, two hundred twenty-five".
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