Base | Representation |
---|---|
bin | 110001100010011010101… |
… | …111110110101011000011 |
3 | 110001102212021022210110011 |
4 | 301202122233312223003 |
5 | 421233310321200103 |
6 | 11123512253445351 |
7 | 500642335260364 |
oct | 61423257665303 |
9 | 13042767283404 |
10 | 3404210334403 |
11 | 10a2798a9368a |
12 | 46b9131a0857 |
13 | 1b9028524a78 |
14 | baa9c321b6b |
15 | 5d840aadd6d |
hex | 3189abf6ac3 |
3404210334403 has 4 divisors (see below), whose sum is σ = 3407673418128. Its totient is φ = 3400747250680.
The previous prime is 3404210334313. The next prime is 3404210334463. The reversal of 3404210334403 is 3044330124043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3404210334403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3404210334463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1731540388 + ... + 1731542353.
It is an arithmetic number, because the mean of its divisors is an integer number (851918354532).
Almost surely, 23404210334403 is an apocalyptic number.
3404210334403 is a deficient number, since it is larger than the sum of its proper divisors (3463083725).
3404210334403 is an equidigital number, since it uses as much as digits as its factorization.
3404210334403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3463083724.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 3404210334403 its reverse (3044330124043), we get a palindrome (6448540458446).
The spelling of 3404210334403 in words is "three trillion, four hundred four billion, two hundred ten million, three hundred thirty-four thousand, four hundred three".
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