Base | Representation |
---|---|
bin | 1111011110110000100111… |
… | …10100110100100110100111 |
3 | 11110112101222110210122010022 |
4 | 13233120103310310212213 |
5 | 13430222003302332101 |
6 | 200222442443545355 |
7 | 10112320345400225 |
oct | 757302364644647 |
9 | 143471873718108 |
10 | 34042243402151 |
11 | a935263a14a26 |
12 | 399974652b25b |
13 | 15cc229006b1a |
14 | 859920bd1b15 |
15 | 3e07b46aca1b |
hex | 1ef613d349a7 |
34042243402151 has 2 divisors, whose sum is σ = 34042243402152. Its totient is φ = 34042243402150.
The previous prime is 34042243402073. The next prime is 34042243402157. The reversal of 34042243402151 is 15120434224043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34042243402151 - 218 = 34042243140007 is a prime.
It is a super-3 number, since 3×340422434021513 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34042243402157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17021121701075 + 17021121701076.
It is an arithmetic number, because the mean of its divisors is an integer number (17021121701076).
Almost surely, 234042243402151 is an apocalyptic number.
34042243402151 is a deficient number, since it is larger than the sum of its proper divisors (1).
34042243402151 is an equidigital number, since it uses as much as digits as its factorization.
34042243402151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92160, while the sum is 35.
Adding to 34042243402151 its reverse (15120434224043), we get a palindrome (49162677626194).
The spelling of 34042243402151 in words is "thirty-four trillion, forty-two billion, two hundred forty-three million, four hundred two thousand, one hundred fifty-one".
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