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34043413153 = 191791758587
BaseRepresentation
bin11111101101001001…
…010100001010100001
310020212112200120110211
4133231021110022201
51024210103210103
623350032254121
72313425144251
oct375511241241
9106775616424
1034043413153
111348a68a1a2
1267210a1341
133296ca6a69
14190d45d961
15d43ac736d
hex7ed2542a1

34043413153 has 4 divisors (see below), whose sum is σ = 35835171760. Its totient is φ = 32251654548.

The previous prime is 34043413123. The next prime is 34043413211. The reversal of 34043413153 is 35131434043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34043413153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34043413123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 895879275 + ... + 895879312.

It is an arithmetic number, because the mean of its divisors is an integer number (8958792940).

Almost surely, 234043413153 is an apocalyptic number.

It is an amenable number.

34043413153 is a deficient number, since it is larger than the sum of its proper divisors (1791758607).

34043413153 is a wasteful number, since it uses less digits than its factorization.

34043413153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1791758606.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 34043413153 its reverse (35131434043), we get a palindrome (69174847196).

The spelling of 34043413153 in words is "thirty-four billion, forty-three million, four hundred thirteen thousand, one hundred fifty-three".

Divisors: 1 19 1791758587 34043413153