Base | Representation |
---|---|
bin | 11111101101001100… |
… | …000101101001010001 |
3 | 10020212121001111200021 |
4 | 133231030011221101 |
5 | 1024210244440423 |
6 | 23350100023441 |
7 | 2313434262544 |
oct | 375514055121 |
9 | 106777044607 |
10 | 34044140113 |
11 | 13490036395 |
12 | 6721391b81 |
13 | 329719c909 |
14 | 190d5ac85b |
15 | d43bbc95d |
hex | 7ed305a51 |
34044140113 has 2 divisors, whose sum is σ = 34044140114. Its totient is φ = 34044140112.
The previous prime is 34044140111. The next prime is 34044140167. The reversal of 34044140113 is 31104144043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33911959104 + 132181009 = 184152^2 + 11497^2 .
It is a cyclic number.
It is not a de Polignac number, because 34044140113 - 21 = 34044140111 is a prime.
Together with 34044140111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (34044140111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17022070056 + 17022070057.
It is an arithmetic number, because the mean of its divisors is an integer number (17022070057).
Almost surely, 234044140113 is an apocalyptic number.
It is an amenable number.
34044140113 is a deficient number, since it is larger than the sum of its proper divisors (1).
34044140113 is an equidigital number, since it uses as much as digits as its factorization.
34044140113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 34044140113 its reverse (31104144043), we get a palindrome (65148284156).
The spelling of 34044140113 in words is "thirty-four billion, forty-four million, one hundred forty thousand, one hundred thirteen".
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