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340443125537 is a prime number
BaseRepresentation
bin1001111010000111111…
…11011101011100100001
31012112202001210200012112
410331003333131130201
521034211420004122
6420221501405105
733411332551334
oct4750377353441
91175661720175
10340443125537
111214212a6099
1255b91869795
1326146941b18
14126984dc61b
158cc80272e2
hex4f43fdd721

340443125537 has 2 divisors, whose sum is σ = 340443125538. Its totient is φ = 340443125536.

The previous prime is 340443125513. The next prime is 340443125551. The reversal of 340443125537 is 735521344043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 315668680336 + 24774445201 = 561844^2 + 157399^2 .

It is a cyclic number.

It is not a de Polignac number, because 340443125537 - 234 = 323263256353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 340443125494 and 340443125503.

It is not a weakly prime, because it can be changed into another prime (340443125837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170221562768 + 170221562769.

It is an arithmetic number, because the mean of its divisors is an integer number (170221562769).

Almost surely, 2340443125537 is an apocalyptic number.

It is an amenable number.

340443125537 is a deficient number, since it is larger than the sum of its proper divisors (1).

340443125537 is an equidigital number, since it uses as much as digits as its factorization.

340443125537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 41.

The spelling of 340443125537 in words is "three hundred forty billion, four hundred forty-three million, one hundred twenty-five thousand, five hundred thirty-seven".