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34047213045 = 353173219813
BaseRepresentation
bin11111101101010111…
…110011110111110101
310020212210211121221120
4133231113303313311
51024212041304140
623350245534153
72313502351536
oct375527636765
9106783747846
1034047213045
11134918450aa
126722414359
133297a07511
14190db6c68d
15d440c81d0
hex7ed5f3df5

34047213045 has 16 divisors (see below), whose sum is σ = 56232817152. Its totient is φ = 17572754880.

The previous prime is 34047212971. The next prime is 34047213049. The reversal of 34047213045 is 54031274043.

It is not a de Polignac number, because 34047213045 - 213 = 34047204853 is a prime.

It is a super-2 number, since 2×340472130452 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34047212997 and 34047213015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34047213049) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36609442 + ... + 36610371.

It is an arithmetic number, because the mean of its divisors is an integer number (3514551072).

Almost surely, 234047213045 is an apocalyptic number.

It is an amenable number.

34047213045 is a deficient number, since it is larger than the sum of its proper divisors (22185604107).

34047213045 is a wasteful number, since it uses less digits than its factorization.

34047213045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73219852.

The product of its (nonzero) digits is 40320, while the sum is 33.

Adding to 34047213045 its reverse (54031274043), we get a palindrome (88078487088).

The spelling of 34047213045 in words is "thirty-four billion, forty-seven million, two hundred thirteen thousand, forty-five".

Divisors: 1 3 5 15 31 93 155 465 73219813 219659439 366099065 1098297195 2269814203 6809442609 11349071015 34047213045