Base | Representation |
---|---|
bin | 110001100010111101010… |
… | …011010010001010100011 |
3 | 110001111100200011021011201 |
4 | 301202331103102022203 |
5 | 421241002223004040 |
6 | 11124050003022031 |
7 | 500662604613622 |
oct | 61427523221243 |
9 | 13044320137151 |
10 | 3404790047395 |
11 | 10a2a66245630 |
12 | 46ba5536a917 |
13 | 1b90bb6696c9 |
14 | bab153076b9 |
15 | 5d876920a9a |
hex | 318bd4d22a3 |
3404790047395 has 16 divisors (see below), whose sum is σ = 4457231906400. Its totient is φ = 2476181939200.
The previous prime is 3404790047383. The next prime is 3404790047497. The reversal of 3404790047395 is 5937400974043.
It is not a de Polignac number, because 3404790047395 - 217 = 3404789916323 is a prime.
It is a super-4 number, since 4×34047900473954 (a number of 51 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (55).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5123565 + ... + 5749825.
It is an arithmetic number, because the mean of its divisors is an integer number (278576994150).
Almost surely, 23404790047395 is an apocalyptic number.
3404790047395 is a deficient number, since it is larger than the sum of its proper divisors (1052441859005).
3404790047395 is a wasteful number, since it uses less digits than its factorization.
3404790047395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 725126.
The product of its (nonzero) digits is 11430720, while the sum is 55.
The spelling of 3404790047395 in words is "three trillion, four hundred four billion, seven hundred ninety million, forty-seven thousand, three hundred ninety-five".
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