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34052100433 = 135349422497
BaseRepresentation
bin11111101101101010…
…011101000101010001
310020220011000221011221
4133231222131011101
51024214314203213
623350542405041
72313562035511
oct375552350521
9106804027157
1034052100433
111349458306a
126723b90781
133298a28c70
141910681841
15d4474138d
hex7eda9d151

34052100433 has 8 divisors (see below), whose sum is σ = 37363408488. Its totient is φ = 30839637504.

The previous prime is 34052100391. The next prime is 34052100437. The reversal of 34052100433 is 33400125043.

It can be written as a sum of positive squares in 4 ways, for example, as 90402064 + 33961698369 = 9508^2 + 184287^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-34052100433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34052100398 and 34052100407.

It is not an unprimeable number, because it can be changed into a prime (34052100437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24710560 + ... + 24711937.

It is an arithmetic number, because the mean of its divisors is an integer number (4670426061).

Almost surely, 234052100433 is an apocalyptic number.

It is an amenable number.

34052100433 is a deficient number, since it is larger than the sum of its proper divisors (3311308055).

34052100433 is a wasteful number, since it uses less digits than its factorization.

34052100433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49422563.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 34052100433 its reverse (33400125043), we get a palindrome (67452225476).

The spelling of 34052100433 in words is "thirty-four billion, fifty-two million, one hundred thousand, four hundred thirty-three".

Divisors: 1 13 53 689 49422497 642492461 2619392341 34052100433