341001220421 has 2 divisors, whose sum is σ = 341001220422. Its totient is φ = 341001220420.

The previous prime is 341001220397. The next prime is 341001220487. The reversal of 341001220421 is 124022100143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 340310056321 + 691164100 = 583361^2 + 26290^2 .

It is an emirp because it is prime and its reverse (124022100143) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-341001220421 is a prime.

It is a super-2 number, since 2×341001220421² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 341001220393 and 341001220402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341001220121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170500610210 + 170500610211.

It is an arithmetic number, because the mean of its divisors is an integer number (170500610211).

Almost surely, 2^341001220421 is an apocalyptic number.

It is an amenable number.

341001220421 is a deficient number, since it is larger than the sum of its proper divisors (1).

341001220421 is an equidigital number, since it uses as much as digits as its factorization.

341001220421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 341001220421 its reverse (124022100143), we get a palindrome (465023320564).

It can be divided in two parts, 34100 and 1220421, that added together give a palindrome (1254521).

The spelling of 341001220421 in words is "three hundred forty-one billion, one million, two hundred twenty thousand, four hundred twenty-one".