341031411212333 has 4 divisors (see below), whose sum is σ = 341266119686748. Its totient is φ = 340796702737920.

The previous prime is 341031411212309. The next prime is 341031411212351. The reversal of 341031411212333 is 333212114130143.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 338539502710249 + 2491908502084 = 18399443^2 + 1578578^2 .

It is a cyclic number.

It is not a de Polignac number, because 341031411212333 - 2¹² = 341031411208237 is a prime.

It is a super-3 number, since 3×341031411212333³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 341031411212333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341031411212533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117354235028 + ... + 117354237933.

It is an arithmetic number, because the mean of its divisors is an integer number (85316529921687).

Almost surely, 2^{341031411212333} is an apocalyptic number.

It is an amenable number.

341031411212333 is a deficient number, since it is larger than the sum of its proper divisors (234708474415).

341031411212333 is a wasteful number, since it uses less digits than its factorization.

341031411212333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234708474414.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 341031411212333 its reverse (333212114130143), we get a palindrome (674243525342476).

The spelling of 341031411212333 in words is "three hundred forty-one trillion, thirty-one billion, four hundred eleven million, two hundred twelve thousand, three hundred thirty-three".