34113251004453 has 6 divisors (see below), whose sum is σ = 49274695895334. Its totient is φ = 22742167336296.

The previous prime is 34113251004421. The next prime is 34113251004491. The reversal of 34113251004453 is 35440015231143.

34113251004453 is a `hidden beast` number, since 3 + 4 + 1 + 132 + 510 + 0 + 4 + 4 + 5 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 34085781919809 + 27469084644 = 5838303^2 + 165738^2 .

It is not a de Polignac number, because 34113251004453 - 2⁵ = 34113251004421 is a prime.

It is a super-2 number, since 2×34113251004453² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34113251004493) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1895180611350 + ... + 1895180611367.

It is an arithmetic number, because the mean of its divisors is an integer number (8212449315889).

Almost surely, 2^{34113251004453} is an apocalyptic number.

It is an amenable number.

34113251004453 is a deficient number, since it is larger than the sum of its proper divisors (15161444890881).

34113251004453 is a wasteful number, since it uses less digits than its factorization.

34113251004453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3790361222723 (or 3790361222720 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 34113251004453 its reverse (35440015231143), we get a palindrome (69553266235596).

The spelling of 34113251004453 in words is "thirty-four trillion, one hundred thirteen billion, two hundred fifty-one million, four thousand, four hundred fifty-three".