3411340003 has 4 divisors (see below), whose sum is σ = 3612007080. Its totient is φ = 3210672928.

The previous prime is 3411339991. The next prime is 3411340021. The reversal of 3411340003 is 3000431143.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3000431143 = 26399 ⋅113657.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3411340003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3411340043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100333513 + ... + 100333546.

It is an arithmetic number, because the mean of its divisors is an integer number (903001770).

Almost surely, 2^3411340003 is an apocalyptic number.

3411340003 is a deficient number, since it is larger than the sum of its proper divisors (200667077).

3411340003 is a wasteful number, since it uses less digits than its factorization.

3411340003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200667076.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 3411340003 is about 58406.6777260957. The cubic root of 3411340003 is about 1505.3644960652.

Adding to 3411340003 its reverse (3000431143), we get a palindrome (6411771146).

The spelling of 3411340003 in words is "three billion, four hundred eleven million, three hundred forty thousand, three".