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341140051 = 748734293
BaseRepresentation
bin10100010101010…
…110001001010011
3212202220201011201
4110111112021103
51144312440201
653503452031
711311433260
oct2425261123
9782821151
10341140051
1116562362a
12962b7017
13558a3525
1433442267
151ee38801
hex14556253

341140051 has 4 divisors (see below), whose sum is σ = 389874352. Its totient is φ = 292405752.

The previous prime is 341140031. The next prime is 341140061. The reversal of 341140051 is 150041143.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150041143 = 721434449.

It is a cyclic number.

It is not a de Polignac number, because 341140051 - 211 = 341138003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (341140031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24367140 + ... + 24367153.

It is an arithmetic number, because the mean of its divisors is an integer number (97468588).

Almost surely, 2341140051 is an apocalyptic number.

341140051 is a deficient number, since it is larger than the sum of its proper divisors (48734301).

341140051 is an equidigital number, since it uses as much as digits as its factorization.

341140051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48734300.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 341140051 is about 18469.9770167697. The cubic root of 341140051 is about 698.7324346398.

Adding to 341140051 its reverse (150041143), we get a palindrome (491181194).

The spelling of 341140051 in words is "three hundred forty-one million, one hundred forty thousand, fifty-one".

Divisors: 1 7 48734293 341140051