Base | Representation |
---|---|
bin | 110001101001000111011… |
… | …100101101011111100011 |
3 | 110002010102112002221110202 |
4 | 301221013130231133203 |
5 | 421343023100213411 |
6 | 11131102104015415 |
7 | 501315511602065 |
oct | 61510734553743 |
9 | 13063375087422 |
10 | 3411402741731 |
11 | 10a5849a04776 |
12 | 47119ba6156b |
13 | 1b99036570aa |
14 | bb181645735 |
15 | 5db1223283b |
hex | 31a4772d7e3 |
3411402741731 has 2 divisors, whose sum is σ = 3411402741732. Its totient is φ = 3411402741730.
The previous prime is 3411402741689. The next prime is 3411402741763. The reversal of 3411402741731 is 1371472041143.
It is a strong prime.
It is an emirp because it is prime and its reverse (1371472041143) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3411402741731 is a prime.
It is a super-2 number, since 2×34114027417312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3411402741781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1705701370865 + 1705701370866.
It is an arithmetic number, because the mean of its divisors is an integer number (1705701370866).
Almost surely, 23411402741731 is an apocalyptic number.
3411402741731 is a deficient number, since it is larger than the sum of its proper divisors (1).
3411402741731 is an equidigital number, since it uses as much as digits as its factorization.
3411402741731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56448, while the sum is 38.
Adding to 3411402741731 its reverse (1371472041143), we get a palindrome (4782874782874).
The spelling of 3411402741731 in words is "three trillion, four hundred eleven billion, four hundred two million, seven hundred forty-one thousand, seven hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •