Base | Representation |
---|---|
bin | 10011111101010010000… |
… | …110101001010010110111 |
3 | 11212010000020121022221002 |
4 | 103331102012221102313 |
5 | 134432233320304033 |
6 | 2530013501313515 |
7 | 201041233001231 |
oct | 23752206512267 |
9 | 4763006538832 |
10 | 1371472041143 |
11 | 489702238596 |
12 | 1a197326589b |
13 | 9c4384c5149 |
14 | 4a5458a7251 |
15 | 25a1d8ab3e8 |
hex | 13f521a94b7 |
1371472041143 has 2 divisors, whose sum is σ = 1371472041144. Its totient is φ = 1371472041142.
The previous prime is 1371472041103. The next prime is 1371472041161. The reversal of 1371472041143 is 3411402741731.
It is a strong prime.
It is an emirp because it is prime and its reverse (3411402741731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1371472041143 - 210 = 1371472040119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1371472041097 and 1371472041106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1371472041103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685736020571 + 685736020572.
It is an arithmetic number, because the mean of its divisors is an integer number (685736020572).
Almost surely, 21371472041143 is an apocalyptic number.
1371472041143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371472041143 is an equidigital number, since it uses as much as digits as its factorization.
1371472041143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56448, while the sum is 38.
Adding to 1371472041143 its reverse (3411402741731), we get a palindrome (4782874782874).
The spelling of 1371472041143 in words is "one trillion, three hundred seventy-one billion, four hundred seventy-two million, forty-one thousand, one hundred forty-three".
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